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有道 F.5 不懂，高手快入!!
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我有道不懂 1. use a calculator to solve the equation on the interval 0~360. round the ans to 2 decimal placescos θ= 0.67a. 0.84,2.41b. 0.84,3.98b. 0.84,2.31c. 0.84,5.452.solve the equation for sulutions in the interval (0,360)square root 2 cos 2θ=13. in a shipment of 20 herrp potter books, 7 have a... 示更多 我有道不懂 1. use a calculator to solve the equation on the interval 0~360. round the ans to 2 decimal places cos θ= 0.67 a. 0.84,2.41 b. 0.84,3.98 b. 0.84,2.31 c. 0.84,5.45 2.solve the equation for sulutions in the interval (0,360) square root 2 cos 2θ=1 3. in a shipment of 20 herrp potter books, 7 have a missing cover, out of a sample of 4, what i the probability that at least 3 have the cover missing? 4. find an expression for the slope of the line tangent to the curve at x, and determine the slope of tangent at the point y=x^2 + 11x - 15 at x=1 a. 11x,11 b. 2x-11,-9 c.2x+11,13 d.11x+15,26 把步列出,量解答.感激分,日後有定要作交流!!!
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1. Use a calculator to solve the equation on the interval 0~360. round the ans to 2 decimal places cos θ= 0.67 a. 0.84,2.41 b. 0.84,3.98 c. 0.84,2.31 d. 0.84,5.45 θ = cos ^-1(0.67) = 0.8366 Only in the 1st quadrant and 4th quadrant, cos θ is positive In the 4th quadrant, θ = 2pi - 0.8366 = 2(3.14159) 0.8366 = 5.44658 Θ = 0.84 or 5.45 (angle in radians) 2. Solve the equation for solutions in the interval (0,360) square root 2 cos 2θ =1 2θ = cos^-1(1/2^0.5) = 45 deg, θ = 22.5 deg 2θ = 360 deg 45 deg = 315 deg = 157.5 deg 2θ = 360 deg + 45 deg = 405 deg = 202.5 deg 2θ = 360 deg + 315 deg = 675 deg = 337.5 deg θ = 22.5 deg, 157.5 deg, 202.5 deg or 337.5 deg (angle in degree) 3. In a shipment of 20 Harry Potter books, 7 have a missing cover, out of a sample of 4, what is the probability that at least 3 have the cover missing? % defective = (7/20)(100) = 35% n = 4 Bernoulli trial, p = 0.65, q = 0.35 In Bernoulli trial the probability of exactly x success or failure is given by n p(x) = ( ) p^x q^(n-x) where q = 1 - p x n n! ( ) = ----------------------- x x! (n - x)! Let X be the number of defective samples You have either 3 or 4 defective samples out of 4 samples P(X>= 3) = p(3) + p(4) 4 p(3) = ( )(0.35)^3(0.65)^1= [4!/(3!)(4-3)!] (0.35)^3(0.65)^1 = 4(0.0428)(0.65) = 0.11147 3 4 p(4) = ( )(0.35)^4(0.65)^0= [4!/(4!)(4-4)!] (0.35)^4(0.65)^0 = 1(0.0428) = 0.015 4 P(X>= 3) = 0.11147+ 0.015 = 0.12647 Out of a sample of 4, the probability that at least 3 have the cover missing is 0.12647 4. Find an expression for the slope of the line tangent to the curve at x, and determine the slope of tangent at the point y=x^2 + 11x - 15 at x=1 Differentiate y with respect to x [Calculus] dy/dx = 2x^(2-1) + 11 = 2x + 11 The slope of the line tangent at x = 1 = 2x + 11 = 2(1) + 11= 13 a. 11x,11 b. 2x-11,-9 c. 2x+11,13 d.11x+15,26 Comment: I did probability very long time ago. I'm not so sure about the answer. Let someone do it.
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