N 个点 分成两排 对这 N 个点进行排序 让他们的交点最少 - V2EX
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chaleaochexist
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N 个点 分成两排 对这 N 个点进行排序 让他们的交点最少

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  •   chaleaochexist 2023-07-06 18:17:43 +08:00 1239 次点击
    这是一个创建于 881 天前的主题,其中的信息可能已经有所发展或是发生改变。

    16886385338481688638532959.png

    上图交点数是 3, 但是我们可以打乱 A1 A2 ... Am B1 B2 ... Bn 的顺序 让他们的交点数变化.

    求算法. 或者关键字.

    穷举的话 m! * n! 数量有点大啊...

    谢谢大佬.

    2 条回复    2023-07-06 21:48:38 +08:00
    xupefei
        1
    xupefei  
       2023-07-06 18:27:51 +08:00 via iPhone   1
    我拍脑袋想了一下,似乎把 incoming 和 outgoing 最少的节点排左边就是最优解?
    onlytmp
        2
    onlytmp  
       2023-07-06 21:48:38 +08:00
    求图的连通分量吧,连通分量之间分开摆放就不会有交点,连通分量内部尽量展开摆放以减少交点
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