需求是对 SPBM 、SPMC 分组,计算 ZJ/CKSL 最小值及其条数,最大值及其条数, 使用的数据库 Oracle 。
SELECT SPBM,SPMC, round( MIN(DJ),5) AS MIN_DJ, sum(CASE WHEN min_rn = 1 THEN sl ELSE 0 END) AS MIN_SL, round( MAX(DJ),5) AS MAX_DJ, sum(CASE WHEN max_rn = 1 THEN sl ELSE 0 END) AS MAX_SL from ( SELECT SPBM, SPMC, ZJ/CKSL as DJ , count(*) as sl, ROW_NUMBER() OVER (PARTITION BY SPBM,SPMC ORDER BY ZJ/CKSL ASC) AS min_rn, ROW_NUMBER() OVER (PARTITION BY SPBM,SPMC ORDER BY ZJ/CKSL DESC) AS max_rn FROM SP GROUP BY SPBM, SPMC,ZJ/CKSL ) WHERE min_rn = 1 OR max_rn = 1 GROUP BY SPBM,SPMC
从运维导出的结果 excel 里发现 MIN_SL,MAX_SL 这两个数量存在小数,不知道为啥?
![]() | 1 Paracosm 2023-06-07 14:48:22 +08:00 数据不匹配或者隐式转换? |
![]() | 2 DOMO 2023-06-07 15:38:14 +08:00 把 count 结果导出来手动加加看呢 |
![]() | 3 HankAviator 2023-06-07 22:10:19 +08:00 ZJ/CKSL 的值拉出来看看? |