这样的一个操作在VI里该怎么实现 - V2EX
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这样的一个操作在VI里该怎么实现

  •  
  •   mongodb 2013-12-21 13:30:20 +08:00 4103 次点击
    这是一个创建于 4369 天前的主题,其中的信息可能已经有所发展或是发生改变。
    编辑一个文件

    形如
    BEGIN

    keyqwertyuiopsdfghjkldfghjkfs
    sdfghjkldfghjkdfghjkl;
    dfghjkdfghjklfghjkl
    sdfghjkl;asdfghjklasdfghjk
    COMMIT
    UPDATE `xxx` set xxxxx

    BEGIN

    keyqwertyuiopsdfghjkldfghjkfs
    sdfghjkldfghjkdfghjkl;
    dfghjkdfghjklfghjkl
    sdfghjkl;asdfghjklasdfghjk
    COMMIT
    UPDATE `xxx` set xxxxx

    BEGIN
    keyqwertyuiopsdfghjkldfghjkfs
    sdfghjkldfghjkdfghjkl;
    dfghjkdfghjklfghjkl
    sdfghjkl;asdfghjklasdfghjk
    COMMIT
    UPDATE `xxx` set xxxxx



    我想删掉其中从BEGIN到COMMIT结束的这个区块
    只保留下各种sql语句

    一开始我想只grep出sql语句到另外的文件,但因为这些语句包含了值后太乱,跨行的,转折的,还有一些错误需要手工修正,只能反过来,把所有从BEGIN到COMMIT的区块都删除。但居然尝试了半天没弄起来,求高手给个例子示范。
    6 条回复    1970-01-01 08:00:00 +08:00
    bravejoe
        1
    bravejoe  
       2013-12-21 13:34:25 +08:00
    :%s/BEGIN\_.\+COMMIT//g
    bravejoe
        2
    bravejoe  
       2013-12-21 13:40:29 +08:00
    %s/BEGIN\_[^\(BEGIN\)]\+COMMIT//g
    xcatliu
        3
    xcatliu  
       2013-12-21 18:40:57 +08:00
    用宏吧
    q1/BEGIN<enter><shift-v>/COMMIT<enter>d<esc>q
    1000q
    xcatliu
        4
    xcatliu  
       2013-12-21 18:41:33 +08:00
    1000@1
    maga
        5
    maga  
       2013-12-23 15:25:40 +08:00
    :v/UPDATE/d
    gongcheng
        6
    gongcheng  
       2013-12-23 18:41:02 +08:00
    二楼是正解。
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