Promise 问题求解 - V2EX
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middle2000
V2EX    Javascript

Promise 问题求解

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  •   middle2000 2023-02-24 16:27:52 +08:00 2004 次点击
    这是一个创建于 1010 天前的主题,其中的信息可能已经有所发展或是发生改变。
     const then = x.then if (typeof then === 'function') { // 1 、 通不过 Promise A+测试 x.then((r) => { ... }, e => { ... }) // 2 、通过 Promise A+测试 then.call(x, (r) => { ... }, e => { ... }) } else { resolve(x) } 

    请教大佬问题出在哪里

    4 条回复    2023-02-25 23:09:15 +08:00
    middle2000
        1
    middle2000  
    OP
       2023-02-24 18:30:56 +08:00
    有大佬帮忙解答下么
    azcvcza
        2
    azcvcza  
       2023-02-25 09:26:23 +08:00
    你要让 x.then 作为函数工作的话
    是不是要写成(x.then((r)=>{...},e=>{...}))();写成 IIFE 来立即调用,你光 x.then()只是往 promise 的 then 数组里加了下一个执行项。
    我看你下边 then.call 是想拿来当函数调用,当函数调用的话那不就得转成 IIFE 了吗
    Opportunity
        3
    Opportunity  
       2023-02-25 10:19:05 +08:00   1
    方法 1 访问了两次 x 的 then 属性,如果是个 getter 的话,会有额外的副作用

    > 3.5 This procedure of first storing a reference to x.then, then testing that reference, and then calling that reference, avoids multiple accesses to the x.then property. Such precautions are important for ensuring consistency in the face of an accessor property, whose value could change between retrievals.
    middle2000
        4
    middle2000  
    OP
       2023-02-25 23:09:15 +08:00
    @Opportunity 了解了,感谢
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