字符串 hash 问题,有 <N 个字符串长度任意,放入到长度为 N 的数组,后续还需要根据这 N 个字符串快速得到位置,怎么样最快呢? - V2EX
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microxiaoxiao

字符串 hash 问题,有 <N 个字符串长度任意,放入到长度为 N 的数组,后续还需要根据这 N 个字符串快速得到位置,怎么样最快呢?

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  •   microxiaoxiao Jul 12, 2022 1350 views
    This topic created in 1424 days ago, the information mentioned may be changed or developed.

    有经验的大佬来指教一下

    3 replies    2022-07-13 10:23:27 +08:00
    amlee
        1
    amlee  
       Jul 12, 2022
    hashmap , key 存字符串 hash ,value 存数组 index
    CEBBCAT
        2
    CEBBCAT  
       Jul 12, 2022 via iPhone
    重新描述一下根本问题呗?
    vvtf
        3
    vvtf  
       Jul 13, 2022
    **后续还需要根据这 N 个字符串快速得到位置**
    这句话看不懂, 找到位置有啥意义? 位置放的也是字符串....
    不过你的字面需求可以用一下代码试试:

    int index = 0;
    map<string, int> map;
    string[] arr;
    for ( str : strings) {
    string key = md5(str);
    int val = map.putIfAbsent(key, index);
    if (null != val) {
    continue;
    }
    arr[index ++] = str;
    }


    // get index by string
    return map.get(md5(str));
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