火车票身份证号的打码真不靠谱！

今天坐火车，发现火车票上的身份证号仅仅把出生月日这四位打了，满打满算不超过 400 种可能性。
另外，最后一位校验码也没有打码，感觉又可以排除不少。

回来简单写了个脚本，验证了一下。发现加上校验码，最终只有不超过 40 种可能性（试了好几个身份证号）。
这码打的，跟没打差不多了。

附上代码：

#!/usr/bin/env python3 # -*- encoding: utf-8 -*- def ID_number_check(num_in): if len(num_in) != 18: return False try: int(num_in[:17]) except: return False check_num=num_in[-1] total_sum=int(num_in[0])*7+int(num_in[1])*9+int(num_in[2])*10+int(num_in[3])*5+int(num_in[4])*8+int(num_in[5])*4+int(num_in[6])*2+int(num_in[7])*1+int(num_in[8])*6+int(num_in[9])*3+int(num_in[10])*7+int(num_in[11])*9+int(num_in[12])*10+int(num_in[13])*5+int(num_in[14])*8+int(num_in[15])*4+int(num_in[16])*2 remain=total_sum%11 if remain == 0: check=1 elif remain == 1: check=0 elif remain == 2: check='X' elif remain == 3: check=9 elif remain == 4: check=8 elif remain == 5: check=7 elif remain == 6: check=6 elif remain == 7: check=5 elif remain == 8: check=4 elif remain == 9: check=3 elif remain == 10: check=2 if str(check_num) == str(check): return True else: return False def ID_number_guess(num_in): num_in=num_in.upper() if len(num_in) != 18: print('请输入 18 位身份证号') exit(1) part1=num_in[:10] part2=num_in[-4:] year=num_in[6:10] MOns=range(1, 13) for Mon in Mons: if Mon in [1, 3, 5, 7, 8, 10, 12]: Days=range(1, 32) elif Mon == 2 and leap_year_check(year): Days=range(1, 30) elif Mon == 2 and not leap_year_check(year): Days=range(1, 29) else: Days=range(1, 31) if len(str(Mon)) == 1: Mon='0' +str(Mon) for Day in Days: if len(str(Day)) == 1: Day='0' +str(Day) num_out=part1 +str(Mon) +str(Day) +part2 if ID_number_check(num_out): print(num_out) def leap_year_check(year): try: year=int(year) except: return False if year % 400 == 0: return True elif year % 100 != 0 and year % 4 == 0: return True else: return False if __name__ == '__main__': ID_number=input('请输入要猜测的身份证号: ') ID_number_guess(ID_number)