求教,这段 SQL 该怎么写…… - V2EX
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KagamineLenKai2
V2EX    MySQL

求教,这段 SQL 该怎么写……

  •  
  •   KagamineLenKai2 2016-08-26 11:22:21 +08:00 4551 次点击
    这是一个创建于 3407 天前的主题,其中的信息可能已经有所发展或是发生改变。


    从上图这张表里,找到每一条记录的前七天之内有没有同一人的记录

    然后生成这张表,请问 SQL 该怎么写 QAQ

    第 1 条附言    2016-08-26 14:51:30 +08:00


    额,直接输出成这个样子就好……但我还是找不到方法TwT

    24 条回复    2016-10-13 23:35:36 +08:00
    KagamineLenKai2
        1
    KagamineLenKai2  
    OP
       2016-08-26 11:23:31 +08:00
    本菜鸡才意识到 V2EX 的发帖器是 Markdown 格式的,为了发个帖还现去百度的 Markdown 语法 /(ㄒoㄒ)/~~
    xujif
        2
    xujif  
       2016-08-26 11:31:17 +08:00
    写可以写出来,不过估计效率堪忧。 select * from table as t1 where not exists (select 1 from table as t2 where t1.name=t2.name and t2.date > date_sub(t1.date,interval 7 day) and t2.date < t1.date);
    KagamineLenKai2
        3
    KagamineLenKai2  
    OP
       2016-08-26 11:45:45 +08:00
    @xujif 啊,谢谢,不过第一个括号里的(select 1 ……这里有点没看懂? 1 是?
    cont
        4
    cont  
       2016-08-26 12:00:50 +08:00
    @KagamineLenKai2 1 是代表第一个字段,就是 select name
    bugsnail
        5
    bugsnail  
       2016-08-26 12:01:25 +08:00
    @KagamineLenKai2 那个是 1 表示 true,配合外面那个 exists
    KagamineLenKai2
        6
    KagamineLenKai2  
    OP
       2016-08-26 12:02:27 +08:00
    @cont
    @bugsnail
    谢谢!
    cont
        7
    cont  
       2016-08-26 12:05:33 +08:00
    @bugsnail 原来是这样,学习了
    luckylion
        8
    luckylion  
       2016-08-26 12:41:10 +08:00
    SELECT COUNT(*) AS total,t.*
    FROM table AS t
    WHERE DATE_SUB(CURDATE(), INTERVAL 14 DAY) <= DATE(`data`) AND DATE_SUB(CURDATE(), INTERVAL 7 DAY) >= DATE(`data`)
    GROUP BY idnumber
    having total > 1
    luckylion
        9
    luckylion  
       2016-08-26 12:44:18 +08:00
    where date_sub(curdate(), INTERVAL 7 DAY) <= date(`data`)
    ebony0319
        10
    ebony0319  
       2016-08-26 12:44:22 +08:00
    我觉得用内联自己连自己。然后比较日期比较。假设表是 tt
    select t1.name,t1.idnumber,t1.date,t1.other, case when datediff(wk,t2.date,t1.date)>7 then 'yes' end AS '<7day' from tt AS t1 inner join tt AS t2 on t1.idnumber=t2.idnumber
    where datediff(wk,t2.date,t1.date)>7
    liyanggyang
        11
    liyanggyang  
       2016-08-26 14:04:34 +08:00
    这个,很容易啊,假设表是 table.
    select name,idnumber,date,other,(case when counts>0 then 'yes' else 'no' end) ) '<7day' from (
    select name,idnumber,date,other,
    (select count(1) from table where idnumber=t.idnumber and name=t.name
    and trunc(date) between trunc(t.date-7) and t.date ) counts
    from table t
    );
    liyanggyang
        12
    liyanggyang  
       2016-08-26 14:05:28 +08:00
    这个,很容易啊,假设表是 table.
    select name,idnumber,date,other,(case when counts>0 then 'yes' else 'no' end) ) "<7day" from (
    select name,idnumber,date,other,
    (select count(1) from table where idnumber=t.idnumber and name=t.name
    and trunc(date) between trunc(t.date-7) and t.date ) counts
    from table t
    );
    liyanggyang
        13
    liyanggyang  
       2016-08-26 14:16:54 +08:00
    select name,idnumber,date,other,(case when counts>0 then 'yes' else 'no' end) "<7day" from (
    select name,idnumber,date,other,
    (select count(1) from table where idnumber=t.idnumber and name=t.name
    and date between trunc(t.date-7) and trunc(t.date)) counts
    from table t
    );
    luckylion
        14
    luckylion  
       2016-08-26 15:03:50 +08:00
    SELECT t.*,if(COUNT(*)>1,"yes","no") AS `<7days`
    FROM table AS t
    where 时间判断自己写
    GROUP BY idnumber
    luckylion
        15
    luckylion  
       2016-08-26 15:11:37 +08:00
    刚才看错了
    SELECT *
    FROM table t
    LEFT JOIN
    (
    SELECT idnumber, IF(COUNT(*)>1,"yes","no") AS `<7days`
    FROM table
    WHERE 时间判断
    GROUP BY idnumber
    ) AS t2 ON t.idnumber=t2.idnumber
    luckylion
        16
    luckylion  
       2016-08-26 15:32:46 +08:00
    SELECT *, IF((
    SELECT 1
    FROM TABLE
    WHERE id < t.`id` AND idnumber = t.`idnumber`
    ORDER BY id
    LIMIT 1),"yes","no") AS `<7days`
    FROM TABLE t
    where 时间段

    [Imgur]( )
    最好能有个自动字段
    KagamineLenKai2
        17
    KagamineLenKai2  
    OP
       2016-08-26 15:42:23 +08:00
    @luckylion 请问一下第二个 SELECT 后面的 1 是什么意思?
    luckylion
        18
    luckylion  
       2016-08-26 16:18:51 +08:00
    就是一个常量,有信息时直接用这个常量代替.速度要比显示出表里的信息速度快些
    select 1 from 可以
    select 2 from 也可以
    select 'aa' from 还可以 O(∩_∩)O
    KagamineLenKai2
        19
    KagamineLenKai2  
    OP
       2016-08-26 16:23:39 +08:00
    @luckylion 这样(⊙o⊙)
    Layne
        20
    Layne  
       2016-08-26 17:36:09 +08:00
    @KagamineLenKai2 因为这里只是要判断是否 exists ,而不关心 exists 的记录的具体字段,但是 sql 语法不允许 select 后面没有 内容,那就用个常量来 填充咯
    zjgsamuel
        21
    zjgsamuel  
       2016-08-26 17:41:50 +08:00
    LZ 有没有考虑以下除了把 SQL 写出来后 结合使用场景 同设计数据库的提些出于查询效率上的意见呢?
    qq316107934
        22
    qq316107934  
       2016-08-26 18:37:30 +08:00 via Android
    做 V 家音乐库?
    javaluo
        23
    javaluo  
       2016-08-27 07:42:24 +08:00 via Android
    select case when count(select idnumber from x where date - interval 7 days)>0

    不过效率很低啊 数据分析还好,线上就不要这么干了
    15115199878
        24
    15115199878  
       2016-10-13 23:35:36 +08:00
    @luckylion 很好,
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