关于网上的一段 POJ1860 代码松弛操作的疑问 - V2EX
razrlele

关于网上的一段 POJ1860 代码松弛操作的疑问

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  •   razrlele Aug 18, 2014 2609 views
    This topic created in 4311 days ago, the information mentioned may be changed or developed.
    http://blog.csdn.net/lyhvoyage/article/details/19281013

    这篇博文的Bellman-Ford 算法代码里面的松弛操作的一部分:

    for(int i = 1; i <= n - 1; i++)
    {
    bool flag = false;
    for(int j = 0; j < C; j++)
    {
    int a = p[j].a, b = p[j].b;
    double r = p[j].rate, c = p[j].cost;
    if(dis[b] < (dis[a] - c) * r)
    {
    dis[b] = (dis[a] - c) * r;
    flag = true;
    }

    }
    if(!flag)
    break;
    这里为什么加一个flag变量呢?
    我把flag去掉了一样可以AC, 并且时间也是0ms, 不是很理解作者在这里加flag的意图.

    对于Bellman-Ford算法还是不怎么理解, 希望有人帮忙解惑一下.
    4 replies    2014-08-18 17:57:14 +08:00
    theJian
        1
    theJian  
       Aug 18, 2014   1
    bellman-ford是通过不断进行“松弛”操作得到最短路的,flag记录的是 是否本轮有节点被松弛,如果没有节点能再“松弛”,最短路也就得出了,可以跳出循环。
    GtDzx
        2
    GtDzx  
       Aug 18, 2014
    这里也有做POJ的小伙伴
    razrlele
        3
    razrlele  
    OP
       Aug 18, 2014
    @GtDzx 弱菜啊弱菜啊,多多指教啊
    wisatbff
        4
    wisatbff  
       Aug 18, 2014
    这种技巧叫剪枝。
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