我被 sntp 的输出困惑了好久，原来这玩意不是时区

$ sntp -c 192.168.0.10 sntp [email protected] (1) Can't open KOD db file /var/lib/sntp/kod for writing: Permission denied 2025-02-28 16:31:12.839708 (-0800) +0.0 +/- 0.014694 192.168.0.10 s1 no-leap 

我就真的一直很困惑，为啥我的日期时间时区都是对的，给我的结果的时区显示的是-0800 呢？

看了下文档：

The default is to write the estimated correct local date and time (i.e. not UTC) to the standard output in a format like: '1996-10-15 20:17:25.123 (+0800) +4.567 +/- 0.089 [host] IP sN' where the '(+0800)' means that to get to UTC from the reported local time one must add 8 hours and 0 minutes, 

彳亍。

+8000 是说你看到的时间再加上 8 个小时是 UTC （实际上是 UTC-8 的西八区）

东八区当然显示-0800 了

做个实验，带上其他 TZ 执行 sntp：

$ TZ=UTC sntp -c 192.168.0.10 sntp [email protected] (1) Can't open KOD db file /var/lib/sntp/kod for writing: Permission denied 2025-02-28 08:33:22.297831 (+0000) +0.0 +/- 0.011989 192.168.0.10 s1 no-leap 

这就对了嘛