求教 Fastapi 如何连续返回数据呀 - V2EX
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reapear
V2EX    Python

求教 Fastapi 如何连续返回数据呀

  •  
  •   reapear 2024-04-11 19:37:56 +08:00 2179 次点击
    这是一个创建于 620 天前的主题,其中的信息可能已经有所发展或是发生改变。

    比如我调用 api 执行一个任务,然后在任务中实时返回消息。类似下面这种逻辑

    @app.get("/") async def root(): for i in range(10): time.sleep(1) yield str(i) 
    9 条回复    2024-04-12 14:51:48 +08:00
    NickLuan
        1
    NickLuan  
       2024-04-11 19:48:52 +08:00
    噗,还能这么写?
    street000
        2
    street000  
       2024-04-11 19:52:20 +08:00   3
    SSE 或 WebSocket
    chaunceywe
        3
    chaunceywe  
       2024-04-11 19:57:51 +08:00
    from fastapi import FastAPI
    from fastapi.responses import StreamingResponse

    app = FastAPI()


    async def fake_video_streamer():
    for i in range(10):
    yield b"some fake video bytes"


    @app.get("/")
    async def main():
    return StreamingResponse(fake_video_streamer())
    datadump
        4
    datadump  
       2024-04-11 20:12:57 +08:00
    @street000 good idea!
    reapear
        5
    reapear  
    OP
       2024-04-11 20:22:33 +08:00
    @street000 感谢,了解了一下 WebSocket 这种是我想要的效果。
    reapear
        6
    reapear  
    OP
       2024-04-11 20:26:17 +08:00
    @chaunceywe 这个好像,会等待所有 yield 结果才一起返回。
    mmdsun
        7
    mmdsun  
       2024-04-12 00:58:44 +08:00 via iPhone   1
    @app.route("/sse", methods=["GET"])
    def write():
    def generate():
    s = "output it token by token test output it token by token test"
    for c in s:
    yield c
    time.sleep(0.02)

    return Response(stream_with_context(generate()))

    用浏览器试试看,输出效果是逐字的。不是整个返回
    TomCN
        8
    TomCN  
       2024-04-12 09:18:17 +08:00   1
    @reapear #6 如果你使用 postman 或者 swagger ,是会接收完成后显示的,你可以试着写一个 get 方法,浏览器直接访问接口,然后就会一部分一部分的显示出来了,前端页面接收的话,要使用 fetch 来请求
    realJamespond
        9
    realJamespond  
       2024-04-12 14:51:48 +08:00
    spring 可以用 defered response 配合长轮询
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