考考你 sql 和其他语言的思维上的区别 - V2EX
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rootzeal
V2EX    数据库

考考你 sql 和其他语言的思维上的区别

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  •   rootzeal 2019-02-03 15:36:52 +08:00 via Android 2723 次点击
    这是一个创建于 2494 天前的主题,其中的信息可能已经有所发展或是发生改变。
    10 条回复    2019-03-03 09:12:14 +08:00
    yuikns
        1
    yuikns  
       2019-02-03 15:45:05 +08:00 via iPad
    sql 当然是自己 join 自己 然后 filter。

    程序语言构造 set 然后 filter
    rootzeal
        2
    rootzeal  
    OP
       2019-02-03 18:16:20 +08:00 via Android
    @yuikns 这有点复杂 可以考虑不用 join 的情况
    FrailLove
        3
    FrailLove  
       2019-02-03 19:10:25 +08:00 via iPhone   1
    a b union all b a group by

    sql 语言要用集合的方式思考问题
    widewing
        4
    widewing  
       2019-02-03 19:21:31 +08:00 via Android
    取交集不用 inner join 用啥
    jjplay
        5
    jjplay  
       2019-02-03 20:12:27 +08:00 via iPhone
    大过年的,饶了我 8
    mingyun
        6
    mingyun  
       2019-02-03 22:36:43 +08:00 via Android
    哈哈,大过年的
    yiyi11
        7
    yiyi11  
       2019-02-04 12:56:50 +08:00 via Android
    @FrailLove 老哥厉害了,sql 做统计真是神器。
    yiyi11
        8
    yiyi11  
       2019-02-04 13:22:27 +08:00 via Android
    @FrailLove 老哥,这样对吗?
    select count (*) / 2 as '互关对数' from
    (
    select uid as a, fid as b from t t1
    union all
    select fid as a, uid as b form t t2
    ) group by a, b having count(*) > 1
    CRVV
        9
    CRVV  
       2019-02-04 19:20:33 +08:00
    用 SQL 至少有两种写法吧

    SELECT count(*) / 2 AS pairs
    FROM user_relation a
    INNER JOIN user_relation b ON a.friend_uid = b.user_id
    WHERE a.user_id = b.friend_uid;

    SELECT count(*) / 2 AS pairs FROM (
    SELECT user_id, friend_uid FROM user_relation
    INTERSECT
    SELECT friend_uid, user_id FROM user_relation) AS subquery;

    个人认为 JOIN 是 SQL 里最普通的写法
    rootzeal
        10
    rootzeal  
    OP
       2019-03-03 09:12:14 +08:00 via Android
    这里是 完整的回答 其实只要把 groupby 一下然后再 cout 过滤出 count 等于 2 的就行 不用 join https://mp.weixin.qq.com/s/VOfzuZ5OaG3imxpTcEM0EA
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