python collections.Ordereddict 源码中, 用来记录有序的结构，怎么理解？不是能看懂为什么这样存储。

代码如下, 其中初始化时root[:] = [root, root, None] 和设置值时last[1] = root[0] = self.__map[key] = [last, root, key] 这边怎么理解呢？谢谢啦

class OrderedDict(dict): 'Dictionary that remembers insertion order' # An inherited dict maps keys to values. # The inherited dict provides __getitem__, __len__, __contains__, and get. # The remaining methods are order-aware. # Big-O running times for all methods are the same as regular dictionaries. # The internal self.__map dict maps keys to links in a doubly linked list. # The circular doubly linked list starts and ends with a sentinel element. # The sentinel element never gets deleted (this simplifies the algorithm). # Each link is stored as a list of length three: [PREV, NEXT, KEY]. def __init__(*args, **kwds): '''Initialize an ordered dictionary. The signature is the same as regular dictionaries, but keyword arguments are not recommended because their insertion order is arbitrary. ''' if not args: raise TypeError("descriptor '__init__' of 'OrderedDict' object " "needs an argument") self = args[0] args = args[1:] if len(args) > 1: raise TypeError('expected at most 1 arguments, got %d' % len(args)) try: self.__root except AttributeError: self.__root = root = [] # sentinel node root[:] = [root, root, None] self.__map = {} self.__update(*args, **kwds) def __setitem__(self, key, value, dict_setitem=dict.__setitem__): 'od.__setitem__(i, y) <==> od[i]=y' # Setting a new item creates a new link at the end of the linked list, # and the inherited dictionary is updated with the new key/value pair. if key not in self: root = self.__root last = root[0] last[1] = root[0] = self.__map[key] = [last, root, key] return dict_setitem(self, key, value) def __delitem__(self, key, dict_delitem=dict.__delitem__): 'od.__delitem__(y) <==> del od[y]' # Deleting an existing item uses self.__map to find the link which gets # removed by updating the links in the predecessor and successor nodes. dict_delitem(self, key) link_prev, link_next, _ = self.__map.pop(key) link_prev[1] = link_next # update link_prev[NEXT] link_next[0] = link_prev # update link_next[PREV] def __iter__(self): 'od.__iter__() <==> iter(od)' # Traverse the linked list in order. root = self.__root curr = root[1] # start at the first node while curr is not root: yield curr[2] # yield the curr[KEY] curr = curr[1] # move to next node def __reversed__(self): 'od.__reversed__() <==> reversed(od)' # Traverse the linked list in reverse order. root = self.__root curr = root[0] # start at the last node while curr is not root: yield curr[2] # yield the curr[KEY] curr = curr[0] # move to previous node def clear(self): 'od.clear() -> None. Remove all items from od.' root = self.__root root[:] = [root, root, None] self.__map.clear() dict.clear(self)